Linear Differential Operators

Linear Differential Operators

Linear differential operators on a function space U.

x|L|u=Lxu(x), Lx=nan(x)dndxn.

Want so solve L|u=|s.

Also consider L|u0=0 which defines the nullspace of N(L).

Invertible

Assume we have some L1L=I on N(L) then u=L1|s+|u0 is the general solution. Note that since the null space has vectors that disappeared, then we must include some linear combination of those in the inverse.

To completely fix a single solution, we must supply boundary conditions on the solution to select which |u0 and which L1.

Particular Solution

L1|s

Homogeneous Solution

|u0.

Definitions

Adjoint

u|A|v=v|A|u=Au|v

Self Adjoint

v|L|u=u|L|v

I.e. abdxw(x)v(x)Lxu(x)=abdxw(x)u(x)(Lxv(x)).

Aside

x|L|uLxu(x).

Theorem

For second order differential operators, Lx=a(x)d2dx2+b(x)ddx+c(x), a(x)>0, a,b,cR. Is self adjoint with respect to the weight w(x)=1a(x)expx0xdxb(x)a(x) and Hermitian for any of these boundary conditions on [a,b]: Dirchlet, Neumann, Robin, Periodic.

Author: Christian Cunningham

Created: 2024-05-30 Thu 21:14

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